A 1.7 kg block is moved at constant speed over a surface for which the coefficient of kinetic friction is 0.27. The displacement is 2 m. It is pushed by a force directed at 25 degrees below the horizontal.

Find the work done on the block by: the force. How do you find the force?

I just answered this. See earlier post

it doesnt work can u help me?

F cos 25 = .27 (mg + F sin 25)

To find the work done on the block by the force, we first need to calculate the magnitude of the force. Here's how you can find it:

1. Start by finding the vertical and horizontal components of the force. The force is directed at 25 degrees below the horizontal, so we need to break it down into its vertical and horizontal components.

The vertical component of the force can be found using the formula: F_vert = F * sin(θ), where F is the magnitude of the force and θ is the angle below the horizontal. In this case, θ is 25 degrees.

The horizontal component of the force can be found using the formula: F_horiz = F * cos(θ), where F is the magnitude of the force and θ is the angle below the horizontal. Again, in this case, θ is 25 degrees.

2. Next, calculate the net force acting on the block. To do this, subtract the force of friction from the horizontal component of the applied force. The force of friction can be calculated using the formula: f_friction = μ * N, where μ is the coefficient of kinetic friction and N is the normal force.

The normal force can be found using the formula: N = m * g, where m is the mass of the block and g is the acceleration due to gravity (approximately 9.8 m/s^2).

3. Once you have the net force, you can calculate the work done on the block by multiplying the net force by the displacement in the direction of the force. In this case, since the force is directed horizontally, the displacement is also horizontal.

The work done is given by the formula: W = F_net * d, where F_net is the net force and d is the displacement.

By following these steps, we can find the magnitude of the force and then calculate the work done on the block by that force.