Posted by Anonymous on Saturday, October 29, 2011 at 2:08pm.
3r5s=4 5r+3s=16 elimination method

alberga  ABC123DOREMI, Saturday, October 29, 2011 at 2:31pm
3r5s= 4
5r+3s= 16
Multiply the 1st equation by 5 and the second by 3...
15r25s= 20
15r+9s=48
Subtract both
34s= 68
divide by 34
s=2
substitute
3r10= 4
3r=6
r=2 
alberga  oscar, Tuesday, February 28, 2012 at 5:44pm
sixty is 5/6 of what number

alberga  JOE, Sunday, December 16, 2012 at 11:59am
60*6
DUH!