Calculate the osmolarity of a 2.0 × 10-3 M Na3PO4 solution. Na3PO4 is an ionic compound and produces an electrolytic solution.

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To calculate the osmolarity of a solution, we need to understand the concept of osmoles and the equation for osmolarity.

Osmolarity is a measure of the concentration of a solute in a solution, expressed in terms of osmoles of solute per liter of solution (osmol/L).

To find the osmolarity of a solution, we need to determine the number of osmoles of the solute present in the solution.

First, let's calculate the number of moles of Na3PO4 in the solution:
- The concentration given is 2.0 × 10^-3 M, which means 2.0 × 10^-3 moles of Na3PO4 per liter of solution.

Next, let's determine the number of particles (osmoles) produced by Na3PO4 when it dissociates into ions.
- Na3PO4 dissociates into 3 Na+ ions and 1 PO4^-3 ion, so the total number of particles formed is 3 + 1 = 4.

Now, we can calculate the osmolarity of the solution:
- Multiply the number of moles of Na3PO4 by the number of particles formed per mole (osmoles per mole). In this case, multiply 2.0 × 10^-3 moles by 4 osmoles per mole.
- The result is 8.0 × 10^-3 osmoles.

Therefore, the osmolarity of the 2.0 × 10^-3 M Na3PO4 solution is 8.0 × 10^-3 osmol/L.