Thursday
March 23, 2017

Post a New Question

Posted by on Saturday, October 29, 2011 at 11:34am.

Using a spring gun, a 4.0-kg steel block is launched up a lubricated ramp made out of steel. The angle of the ramp was measured to be 38.8ยบ. The inital speed of the block was 12.0 m/s.

(a) Determine the vertical height that the block reaches above its launching point.
(b) What speed does the block have when it sldes back to its startin point?

  • physics - , Sunday, October 30, 2011 at 2:56pm

    Vo = 12m/s @ 38.8 Deg.
    Xo = 12cos38.8 = 9.35m/s.
    Yo = 12sin38.8 = 7.5m/s.

    a. h = (Yf^2 - Yo^2) / 2g,
    h = (0 - (7.5)^2) / -19.6 = 2.88m.

    b. Yf^2 = Yo^2 + 2g*d,
    Yf^2 = 0 + 19.6*2.88 = 56.4,
    Yf = 7.5m/s.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question