If 5.20 g of HCl is added to enough distilled water to form 3.00 L of solution, what is the molarity of the

solution? [Use molecular weight: HCl, 36.46 amu]

Molarity = moles of solute / Liters of solution

moles = mass given / molar mass
substituting,
Molarity = (5.20/36.46)/3
Molarity = 0.0475 M

hope this helps~ :)

Well, when it comes to molarity, we need to consider the number of moles of solute (in this case, HCl) and the volume of the solution.

First, let's calculate the number of moles of HCl we have. We can do this using the formula:

moles = mass/molecular weight

Substituting the values, we get:

moles = 5.20 g / 36.46 g/mol

Calculating that out gives us approximately 0.1426 moles of HCl.

Since we are looking for the molarity of the solution, we divide the number of moles by the volume (in liters) of the solution:

molarity = moles/volume

Substituting the values, we have:

molarity = 0.1426 moles / 3.00 L

Calculating that out gives us approximately 0.0475 M.

So, the molarity of the solution is approximately 0.0475 M. Now, that wasn't too acidic, was it?

To find the molarity of the solution, we first need to calculate the number of moles of HCl present in the solution.

Step 1: Calculate the number of moles of HCl.

Given mass of HCl = 5.20 g
Molecular weight of HCl = 36.46 g/mol

Number of moles = Mass / Molecular weight
Number of moles of HCl = 5.20 g / 36.46 g/mol

Step 2: Calculate the volume of the solution.

Given volume of the solution = 3.00 L

Step 3: Calculate the molarity of the solution.

Molarity = Number of moles / Volume of solution
Molarity = (5.20 g / 36.46 g/mol) / 3.00 L

Now, let's calculate the molarity:

Molarity = (5.20 g / 36.46 g/mol) / 3.00 L
Molarity = 0.142 mol / 3.00 L

Therefore, the molarity of the solution is approximately 0.0473 M.

To find the molarity of a solution, we need to know the moles of solute (HCl) and the volume of the solution.

First, let's calculate the moles of HCl present in 5.20 g. We can use the molecular weight of HCl to convert grams to moles.

Molecular weight (HCl) = 36.46 g/mol

Moles of HCl = Mass of HCl / Molecular weight (HCl)
= 5.20 g / 36.46 g/mol

Now, let's calculate the volume of the solution. The question states that enough distilled water is added to form 3.00 L of solution. Therefore, the volume of the solution is 3.00 L.

Now, we can find the molarity (M) of the solution using the formula:

Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity = Moles of HCl / Volume of solution
= Moles of HCl / 3.00 L

Substituting the value of moles of HCl, we can calculate the molarity:

Molarity = (5.20 g / 36.46 g/mol) / 3.00 L

Simplifying the expression, we get the molarity of the solution.