(3 tan^2x-1)(tan^2-3)= 0
so 3tan^2x = 1 or tan^2x = 3
tan^2x = 1/3 or tan^2x = -3
the second part has no solution, since something^2 cannot be negative
tanx = ± 1/√3
so x is in any of the 4 quadrants.
form the 30-60-90 triangle we know that
so in degrees, x = 30°, 150°, 210° and 330°
It appears that we are to give the answers in radians, and you seem to know very little about radians.
I am sure your texbook has a unit on it, or else you can learn about it on the thousands of webpages found after googling "radians"
in short, πradians = 180°
so π/6 = 30° , by dividing both sides of the equation above by 6
150° = 5π/6
210° = 7π/6
330° = 11π/6
Your equation is already factored. You have a solution if either factor is zero.
tan^2x can be either 1/3 or 3
tan x = +or- 1/sqrt3
tanx = +or- sqrt3
x = 30, 60, 120, 150, 210, 240, 300 or 330 degrees
pi/6 radians (30 degrees) is only one of the answers.
Go with drwls solution.
somehow my +3 changed into a -3 for the second factor. there are 4 more solutions from that, as drwls shows.
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