Posted by Anonymous on Friday, October 28, 2011 at 6:28pm.
2(xy)(x dy/dx + y) + x dy/dx + y - 1 = 0
plug in (-11,0)
2(-11)(0)(-11dy/dx + 0) + (-11)dy/dx + 0 - 1 = 0
-11 dy/dx = 1
dy/dx = -1/11
so now you have the slope -1/11 and the point(-11,0),
equation of tangent:
0 = -1/11(-11) + b
0 = 1+b --> b= -1
y = (-1/11)x - 1
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