Sunday

December 21, 2014

December 21, 2014

Posted by **Alex** on Friday, October 28, 2011 at 6:19pm.

(a) What is the maximum height the arrow will attain?

(b) The target is at the height from which the arrow was shot. How far away is it?

- Physics -
**bobpursley**, Friday, October 28, 2011 at 7:50pmat the max height, velocity vertical is zero.

Vf=0=54*sin29deg - g*t

solve for t. then put it in this:

hmax=54*sin29*t-1/2 g t^2

distance target:= 54cos29*(2t) where t is the time to the max height, 2t is the total time in the air.

- Physics -
**Alex**, Sunday, October 30, 2011 at 5:00pmSIMPLIFY.

**Answer this Question**

**Related Questions**

Physics - An arrow is shot at 29.0° above the horizontal. Its initial speed is ...

Physics - An arrow is shot a 30.0° above the horizontal. Its velocity is 49 m/s ...

Physics - An arrow is shot at an angle of above the horizontal. The arrow hits a...

Physics - An archer shoots an arrow that leaves the bow at an angle of 42 ...

Physics - An archer shoots an arrow that leaves the bow at an angle of 42 ...

physic - 1)a pitched ball is hit by a batter at a 45 degree angle and just ...

Physics - An archer wishes to shoot an arrow at a target at eye level a distance...

physics - An archer shoots a 54.6 g arrow horizontally at a target 14.0 m away. ...

Algebra 2 - An archer releases an arrow from a shoulder height of 1.39 m. When ...

algebra - An archer releases an arrow from a shoulder height of 1.39 m. When ...