Posted by **Alex** on Friday, October 28, 2011 at 6:19pm.

An arrow is shot at 29.0° above the horizontal. Its initial speed is 54 m/s and it hits the target.

(a) What is the maximum height the arrow will attain?

(b) The target is at the height from which the arrow was shot. How far away is it?

- Physics -
**bobpursley**, Friday, October 28, 2011 at 7:50pm
at the max height, velocity vertical is zero.

Vf=0=54*sin29deg - g*t

solve for t. then put it in this:

hmax=54*sin29*t-1/2 g t^2

distance target:= 54cos29*(2t) where t is the time to the max height, 2t is the total time in the air.

- Physics -
**Alex**, Sunday, October 30, 2011 at 5:00pm
SIMPLIFY.

## Answer This Question

## Related Questions

- Physics - An arrow is shot at 29.0° above the horizontal. Its initial speed is ...
- Physics - An arrow is shot at 28.0 degrees above the horizontal. Its velocity is...
- Physics - An arrow is shot a 30.0° above the horizontal. Its velocity is 49 m/s ...
- physic - 1)a pitched ball is hit by a batter at a 45 degree angle and just ...
- Algebra 2 - An archer releases an arrow from a shoulder height of 1.39 m. When ...
- algebra - An archer releases an arrow from a shoulder height of 1.39 m. When ...
- Physics - An archer shoots an arrow that leaves the bow at an angle of 42 ...
- Physics - An archer shoots an arrow that leaves the bow at an angle of 42 ...
- Physics - An arrow is shot from a height of 1.5 m toward a cliff of height . It ...
- Physics - An arrow is shot from a height of 1.4 m toward a cliff of height H. It...

More Related Questions