Posted by DJ on Friday, October 28, 2011 at 6:18pm.
cross-multiply first
y = x^3 - 7x + 9x^2y - 63y
y' = 3x^2 - 7 + 9x^2y' + 18xy - 63y' , where y' = dy/dx
64y' - 9x^2y' = 3x^2 + 18xy-7
y' = dy/dx = (3x^2 + 18xy - 7)/(64 - 9x^2)
I will leave it up to you to do the remaining arithmetic
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