Post a New Question
posted by Anonymous on Friday, October 28, 2011 at 3:57pm.
find max and min of e^x-e^(3x) on interval where x is greater than or equal to 0 and less than or equal to 1
Since e^3x > e^x when x > 0, min at x=0: e^0 - e^0 = 0 max at x=1: e^3 - e^1
More Related Questions