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March 3, 2015

March 3, 2015

Posted by **Anonymous** on Friday, October 28, 2011 at 3:57pm.

- calculus -
**Steve**, Friday, October 28, 2011 at 5:38pmSince e^3x > e^x when x > 0,

min at x=0: e^0 - e^0 = 0

max at x=1: e^3 - e^1

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