Posted by Xie on .
how to find derivative of (2+cotx)/(7tanx)

trignometry 
Jai,
the derivative of cot x = csc^2 x
the derivative of tan x = sec^2 x
.. and you do this:
[ low*d(high)  high*d(low) ] / (low)^2
where
high = numerator
low = denominator
d(high) and d(low) = respective derivatives