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April 1, 2015

April 1, 2015

Posted by **Peter** on Friday, October 28, 2011 at 1:05am.

- Algebra 2 -
**Steve**, Friday, October 28, 2011 at 11:27amAs you know from the Remainder Theorem, dividing p(x) by (x-a) gives f(a) as the remainder.

we have f(-2) = 7

f(-2) = 4 + 6 + 2k = 7

2k = -3

k = -3/2

So, we have x^2 - 3k - 3

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