Posted by **hannah** on Thursday, October 27, 2011 at 11:57pm.

how do u find the derivative of (csc x)^7 -cos 4x???

- derivatives -
**Reiny**, Friday, October 28, 2011 at 12:04am
You should have a list handy for the basic trig function derivatives

so if y = (csc x)^7 -cos 4x

dy/dx = 7(csc x)^6 ( -csc x)(cotx) + 4sin(4x)

etc

- derivatives -
**hannah**, Friday, October 28, 2011 at 12:15am
Thanks. My teacher told us we need to use the chain rule in these problems, and i'm having trouble figuring out when and where to use it.

- derivatives -
**Reiny**, Friday, October 28, 2011 at 12:38am
I did use the chain rule in finding the derivative of

(csc x)^7

- derivatives -
**hannah**, Friday, October 28, 2011 at 12:50am
I know. I just realized that I messed up what goes where when I was doing it myself. My problem is applying it to other problems, esp when i also have to use the quotient or product rule.

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