cancel 2n to get
This kind of equation can be readily solved by trial and error, since they both increase monotonically at different rates.
In this case, n=1 (which is rejected) or n=8.
try (b) and (2)similarly to (a) above.
3(a) simplifies well, assuming you have left out the critical square brackets:
Give a try to 3b.
What it is saying is that
n!/(n-r)! = 2*n!/((n-r)!r!)
Cancel the n! and (n-r)! to get
=> r!=2 => r=2
After that, you only have to check by trial and error C(n,2)=253.
Give (5) a try.
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