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November 29, 2014

November 29, 2014

Posted by **Anonymous** on Thursday, October 27, 2011 at 9:41pm.

- Calculus -
**bobpursley**, Thursday, October 27, 2011 at 9:56pmdistance=sqrt((x+5)^2+ (y)^2)

but y=3x-4

distance= sqrt((x+5)^2 + (3x-4)^2)

I think it will be easier to do this..

distance^2=((x+5)^2+(3x-4)^2) then take the deravative

2distane*ddistan/dx=0=2(x+5)+2(3x-4)*3

or x+5=-9x+12 check that, then solve for x, then solve for y on the line

check my work, I did it all in my head and on the keyboard.

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