Homework Help: math

Posted by jr on Thursday, October 27, 2011 at 8:13pm.

A 1000搔g car traveling with a velocity of 13搶/s north collides head-on with a 2000搔g truck traveling with a velocity of 17搶/s south. Immediately after the collision, the velocity of the car is 11搶/s south. Taking north as the positive direction, what is the velocity of the truck immediately after the collision?

math - bobpursley, Thursday, October 27, 2011 at 8:50pm
conservation of momentum:

momentum before= momentum after

N means North, S means South, and N=-S

1000*13N+2000*17S=1000*11S+2000*V

13000N+34000(-N)=11000(-N)+2000V

do a little algebra, and solve for V
In my head, I get

V= (11000-21000)N/2000= 10m/s S

check that
math - jen, Thursday, October 27, 2011 at 9:23pm
Thank you sooo much!!! I wasnt dividing by the right number!
can you also explain how to find the impulse of this problem?

A large truck with a mass of 6500搔g and going 20搶/s east collides with a car whose mass is 1100搔g and which is at rest. If the impulse exerted on the car by the truck is 12000意新 east, find the impulse exerted by the car on the truck. Take east as the postive direction

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