Suppose the mass of ball F is 0.5·kg. What is the impulse delivered to the ball by the floor?

Ball going south at velocity 4 m/s, hits floor and returns north velocity at 1 m/s

To find the impulse delivered to the ball by the floor, we need to use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum it undergoes.

The momentum of an object is calculated by multiplying its mass by its velocity. So, let's calculate the initial momentum of the ball when it is going south:

Initial momentum = mass × velocity
= 0.5 kg × 4 m/s
= 2 kg·m/s (south)

Next, we need to calculate the final momentum of the ball when it returns north. Since the direction changes, we need to account for the negative direction:

Final momentum = mass × velocity
= 0.5 kg × (-1 m/s)
= -0.5 kg·m/s (north)

The change in momentum is the difference between the final and initial momentum:

Change in momentum = Final momentum - Initial momentum
= -0.5 kg·m/s - 2 kg·m/s
= -2.5 kg·m/s

Therefore, the impulse delivered to the ball by the floor is -2.5 kg·m/s. The negative sign indicates that the impulse is in the opposite direction of the initial momentum, as the ball changes direction.