Posted by Jane on Thursday, October 27, 2011 at 6:50pm.
1) consider the number of grid paths from the orgin in a coordinate graph to each of the following points:
a) (4,7) b) (3,7) c) (4,6)
2) simplify: (n-r)! / (n-r+1)!
3) solve (n+2)!/ (n-1)! = 210
- Data management - MathMate, Thursday, October 27, 2011 at 8:59pm
It's like finding the number of ways to arrange 4 1's and 7-0's.
The number of ways is given by (m+n)!/(m!n!)
Experiment first with a grid of 2x2, and then a 2x3.
(n+2)!/(n-1)! = 210
(1.2.3...(n+2))/(1.2.3...(n-1)) = 210
n.(n+1).(n+2) = 210
Start with cube root of 210 = 5.9...
so try 5.6.7=210 OK.
- Data management - Anonymous, Thursday, October 27, 2011 at 9:19pm
thank even though im not sure if u woule see this
- Data management - MathMate, Thursday, October 27, 2011 at 10:47pm
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