Mrs. Scott decided that she would spend no more than $120 to buy a jacket and a skirt.f the price of the jacket was $20 more than 3 times the price of the skirt, find the highest possible price of the skirt. How to set up this

j + s <= 120

j = 20 + 3s

20+3s + s <= 120
20 + 4s <= 120
4s <= 100
s <= 25

s <= 25

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25 bruh

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>25

To set up this problem, let's use the following variables:

Let's call the price of the skirt "x" (in dollars).
Since the price of the jacket is $20 more than 3 times the price of the skirt, we can calculate it as follows: 3x + $20.

Now, we are given that Mrs. Scott will spend no more than $120 for both the jacket and the skirt. So, we can set up the equation as follows:

x + (3x + $20) ≤ $120

This equation represents the total cost of the skirt and jacket being less than or equal to $120. Now, we can solve this equation to find the maximum possible price for the skirt.