Posted by **Jason** on Thursday, October 27, 2011 at 6:08pm.

Of the nine (Ann, Ben, Cal, Dot, Ed, Fran, Gail, Hal and Ida), five of them stand in a row for a picture, how many ways can this be done if Ed and Gail are standing next to each other in the picture?

- Discrete Math -
**MathMate**, Thursday, October 27, 2011 at 9:15pm
Take out Ed and Gail (7 people left). Choose 5 at a time to take pictures without the couple. There are

N1=7!/(7-2)! possible pictures.

Now treat the couple as a single person, and get 3 other people for pictures (N2).

Don't forget to ask Gail and Ed to change places (2*N2)

Add up the two to get the total=N1+2N2

## Answer this Question

## Related Questions

- math - annie,betty,Cathy and Danial are going to stand on a row for taking ...
- math - Keith, Anne, Elizabeth, and Marcus are taking a picture. how many ...
- discrete math - Nine people on a baseball team are trying to decide who will ...
- Combinatorics - There are two rows of seats in the classroom and each row has ...
- Math - Tell me how to figure out these probabilities In how many different ...
- math - There are five girls and five boys at a party. In how many ways can they...
- ~*Math Probability*~ - Which expression would you use to figure out the number ...
- Math - Vectors - If "u = (2,2,-1)", "v = (3,-1,0)" and "w = (1,7,8)", verify ...
- Math - Could someone please help me out with the data homework? All I need is ...
- Permutations - 1. 4! a.) 3 b.) 6 c.) 12 d.) 24****** 2. 5! a.) 25******** b.) ...

More Related Questions