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physics

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Suppose a 46-N sled is resting on packed snow. The coefficient of kinetic friction is 0.11. If a person weighing 625 N sits on the sled, what force is needed to pull the sled across the snow at constant speed?

  • physics - ,

    Ws = 46N. = Weight of sled.

    Fs = 46N @ 0deg. = Force of sled.
    Fp = 46sin(0) = 0=Force parallel to the snow.
    Fv = 46cos(0) = 46N. = Force perpendicular to the snow.

    Ff = u(Fv+625),
    Ff = 0.11(46 + 625) = 671N. = Force of
    friction.

    Fn = Fap - Fp - Ff = 0,
    Fap - 0 - 671 = 0,
    Fap = 671N. = Force applied to pull sled.

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