Posted by **Michelle** on Thursday, October 27, 2011 at 3:24pm.

Find the area of the region enclosed between y = 2sin (x) and y = 2cos (x) from x = 0 to x = pi/4.

Thanks for your help :)

- Calculus -
**Steve**, Thursday, October 27, 2011 at 5:04pm
Since cos x > sin x on the interval,

Integrate 2cos x - 2sin x on [0,pi/4]

2sin x + 2cos x [0,pi/4]

at x=pi/4, 2(1/√2 + 1/√2) = 2*2/√2 = 2√2

at x=0, 2*0 + 2*1 = 2

area = 2√2 - 2

## Answer This Question

## Related Questions

- Calculus - Find the area of the region enclosed between y=4sin(x) and y=2cos(x) ...
- Calculus - Find the area of the region enclosed by the given curves: y=e^6x, y=...
- Calc 2: Area under the curve - Find the area of the region enclosed between y=...
- Calculus - Determine the area of the region enclosed by the limaçon r=5+2sin(...
- Calculus-Area between curves - Sketch the region enclosed by the given curves. ...
- Calculus Area between curves - Sketch the region enclosed by the given curves. ...
- calculus - the region enclosed by 2y=5xy=5 and 2y+3x=8. Decide whether to ...
- calculus - Sketch the region enclosed by the given curves. Decide whether to ...
- calculus - find the value of m so that the line y = mx divides the region ...
- Calculus - Any help will be appreciated! Find the area of the region between x=-...

More Related Questions