Tuesday

September 30, 2014

September 30, 2014

Posted by **Michelle** on Thursday, October 27, 2011 at 3:24pm.

Thanks for your help :)

- Calculus -
**Steve**, Thursday, October 27, 2011 at 5:04pmSince cos x > sin x on the interval,

Integrate 2cos x - 2sin x on [0,pi/4]

2sin x + 2cos x [0,pi/4]

at x=pi/4, 2(1/√2 + 1/√2) = 2*2/√2 = 2√2

at x=0, 2*0 + 2*1 = 2

area = 2√2 - 2

**Answer this Question**

**Related Questions**

Calculus - Find the area of the region enclosed by the given curves: y=e^6x, y=...

Calc 2: Area under the curve - Find the area of the region enclosed between y=...

Calculus - Determine the area of the region enclosed by the limaçon r=5+2sin(...

Calculus-Area between curves - Sketch the region enclosed by the given curves. ...

Calculus Area between curves - Sketch the region enclosed by the given curves. ...

calculus - the region enclosed by 2y=5xy=5 and 2y+3x=8. Decide whether to ...

calculus - find the value of m so that the line y = mx divides the region ...

Calculus - Sketch the region enclosed by the given curves. Decide whether to ...

math - the problem is 2cos^2x + sinx-1=0 the directions are to "use an identity ...

Calculus 2 - Sketch the region enclosed by y=e^2x, y=e^6x, and x=1. Decide ...