Tuesday
March 28, 2017

Post a New Question

Posted by on .

An object is thrown straight upwards from the ground at 28 m/s. Due to air resistance (a non-conservative force), the object loses 31.4 percent of its initial energy during its trip to reach maximum height. How much higher does the object travel if there was no air resistance? Answer in meters.

  • PHYSICS - ,

    Vo = 28m/s with no air resistance.
    h1 = (Vf^2 - Vo^2) / 2g,
    h1 = (0 - (28)^2) / -19.6 = 40m.

    Vo = 28 * (100%-31.4%)/100% = 18.452m/s
    with air res.
    h2 = (0 - (18.452)^2) / -19.6 = 17.4m.

    h=hi - h2 = 40 - 17.4 = 22.63m. higher
    with no air res.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question