Posted by **Anonymous** on Thursday, October 27, 2011 at 1:48pm.

A rectangle is inscribed with its base on the x -axis and its upper corners on the parabola

y= 11-x^2.

What are the dimensions of such a rectangle with the greatest possible area?

- Calculus -
**Steve**, Thursday, October 27, 2011 at 4:16pm
The area of the rectangle with corners (-x,0), (x,0) (-x,y) (x,y) is

a = 2x * (11-x^2)

a = 22x - 2x^3

da/dx = 22 - 6x^2

da/dx = 0 when x = √(11/3)

So, the rectangle is 2√(11/3) x 22/3 with area 44/3 * √(11/3) = 28.08

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