NaOH + CH3COOH = CH3COONa + H2O calculate the mass concentration in gdm-3 of the orinigal viniger
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To calculate the mass concentration (also known as the molarity) in g/dm³ of the original vinegar solution, we need the following information:
1. The molar mass of acetic acid (CH₃COOH):
- Carbon (C) - Atomic mass = 12.01 g/mol
- Hydrogen (H) - Atomic mass = 1.01 g/mol
- Oxygen (O) - Atomic mass = 16.00 g/mol
- Total molar mass = (3 × C) + (4 × H) + (2 × O)
2. The balanced equation:
NaOH + CH₃COOH = CH₃COONa + H₂O
3. The stoichiometric ratio:
From the balanced equation, we can see that one mole of NaOH reacts with one mole of CH₃COOH to produce one mole of CH₃COONa.
4. The volume of vinegar solution used.
Now, let's assume that we know the molar mass of acetic acid (CH₃COOH) is approximately 60.05 g/mol.
To calculate the mass concentration in g/dm³, follow these steps:
1. Measure the volume of vinegar solution used (in dm³).
2. Calculate the number of moles of acetic acid (CH₃COOH) in the vinegar solution:
- Moles = (volume in dm³) × (mass concentration in mol/dm³)
3. Calculate the mass of acetic acid (CH₃COOH) in grams:
- Mass (in grams) = Moles × molar mass of CH₃COOH
For a more accurate mass concentration, you would need to know the actual molar mass of acetic acid (CH₃COOH) and the volume of the vinegar solution used. The molar mass provided above is an approximation.