Post a New Question

physics

posted by on .

in a certain system,the water used for storage is initially at 70 degree Celsius and it is required to provide an average of 7.5 kW to keep the house at an average of 18 degree Celsius for 3 days,how much water is needed.

  • physics - ,

    Q = Pt = mc(T2-T1)
    where
    Q = heat/energy (in J)
    P = Power (in W)
    t = time (in s)
    m = mass (in kg)
    c = specific heat capacity (in J/kg-K) = 4.184 J/kg-K for water
    T = temperature (in C or K)
    we're solving for mass. substituting,
    (7.5*1000)*(3*24*60*60) = m*4.184*(70-18)
    1944000000 = 217.568m
    m = 8935137.5 kg = 8935.14 tons of water

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question