Posted by Sami on .
A ball of radius 0.2m rolls along a horizontal table top with a constant linear speed of 3.04 m/s. The ball rolls off the edge and falls a vertical distance of 2.02m before hitting the floor. What is the angular displacement of the ball while it is in the air.
Angular spin rate (w) remains the same after falling off the edge. Multiply w by the time it takes to fall 2.02 m.
w = V/R
Time to fall H = sqrt(2H/g)
= 0.642 s when H = 2.02 m