Wednesday

April 1, 2015

April 1, 2015

Posted by **Iamdumb** on Wednesday, October 26, 2011 at 11:09pm.

- Physics help please -
**drwls**, Wednesday, October 26, 2011 at 11:51pmUse the distance that the bullet and block travel after impact (X = 0.0500 m)to get the initial kinetic energy of bullet and block together.

(Friction force)*(distance)

= (1/2)(M+m) Vo^2

M + m = 12.0132 kg

Friction force = (0.190)(M+m) g

= 22.37 N

Solve for Vo

Once you have Vo, compute the initial momentum (M+m) Vo

That equals the initial momentum of the bullet. Divide that by bullet mass m for the bullet's velocity.

**Answer this Question**

**Related Questions**

physics - A 20 g bullet moving horizontally with a speed v hits a 2-kg block of ...

Physics - 1. A bullet of 0.0500 kg is fired into a block of wood. Knowing that ...

physics - A block of wood with a mass of 1300g is sitting on a horizontal ...

physics - An 7.95 g bullet is fired horizontally into a 9.03 kg block of wood on...

physics - A 25 g bullet is fired from a gun into a 1.35 kg block of wood ...

physics - A gun is fired vertically into a 1.55 kg block of wood at rest ...

Momentum - A 4.4 g bullet is fired into a block of wood with a mass of 21.3 g. ...

physics - A 5kg bullet fired from a gun at 725m/s becomes embedded in a .50kg ...

physics - A 0.0160-kg bullet traveling horizontally at 396 m/s strikes a 3.95-kg...

physics. need help fast - A 5kg bullet fired from a gun at 725m/s becomes ...