Math
posted by Bob on .
How high will a baseball that is thrown up into the air at 48 feet per second go if it starts its flight at a height 10 feet above the ground?

height = 16t^2 + 48t + 10
d(height)/dt = 32t + 48
= 0 at max height
32t=48
t = 48/32 = 1.5
so at 1.5 seconds,
height = 16(1.5)^2 + 48(1.5) + 10 = 59.5 ft
check my arithmetic