Posted by **Hannah** on Wednesday, October 26, 2011 at 10:18pm.

How do you do the derivative of an inverse trig function?

arcsin (sqrt2/2)??

- Calc -
**bobpursley**, Wednesday, October 26, 2011 at 10:29pm
arcsin(sqrt2/2 ) is a constant. The derivative of a constant is zero.

- Calc -
**Hannah**, Wednesday, October 26, 2011 at 10:29pm
oops mixed up 2 questionss haha

- Calc -
**Hannah**, Wednesday, October 26, 2011 at 10:31pm
to find an arcsin you would just have to memorize the unit circle right? so arccos of -sqrt3/2 is 5pi/6?

- Calc -
**bobpursley**, Wednesday, October 26, 2011 at 10:33pm
yes, that is the easy way.

- Calc -
**Steve**, Thursday, October 27, 2011 at 11:10am
However, to find the derivative of an inverse trig function, go through the back door, as it were

y = arcsin(x)

sin y = x

cos y y' = 1

y' = 1/cos x = 1/√(1-sin^{2}x) = 1/√(1-x^{2})

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