Posted by Hannah on Wednesday, October 26, 2011 at 10:18pm.
How do you do the derivative of an inverse trig function?
Calc - bobpursley, Wednesday, October 26, 2011 at 10:29pm
arcsin(sqrt2/2 ) is a constant. The derivative of a constant is zero.
Calc - Hannah, Wednesday, October 26, 2011 at 10:29pm
oops mixed up 2 questionss haha
Calc - Hannah, Wednesday, October 26, 2011 at 10:31pm
to find an arcsin you would just have to memorize the unit circle right? so arccos of -sqrt3/2 is 5pi/6?
Calc - bobpursley, Wednesday, October 26, 2011 at 10:33pm
yes, that is the easy way.
Calc - Steve, Thursday, October 27, 2011 at 11:10am
However, to find the derivative of an inverse trig function, go through the back door, as it were
y = arcsin(x)
sin y = x
cos y y' = 1
y' = 1/cos x = 1/√(1-sin2x) = 1/√(1-x2)
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