Posted by Hannah on .
How do you do the derivative of an inverse trig function?
arcsin (sqrt2/2)??

Calc 
bobpursley,
arcsin(sqrt2/2 ) is a constant. The derivative of a constant is zero.

Calc 
Hannah,
oops mixed up 2 questionss haha

Calc 
Hannah,
to find an arcsin you would just have to memorize the unit circle right? so arccos of sqrt3/2 is 5pi/6?

Calc 
bobpursley,
yes, that is the easy way.

Calc 
Steve,
However, to find the derivative of an inverse trig function, go through the back door, as it were
y = arcsin(x)
sin y = x
cos y y' = 1
y' = 1/cos x = 1/√(1sin^{2}x) = 1/√(1x^{2})