Posted by Hannah on Wednesday, October 26, 2011 at 10:18pm.
How do you do the derivative of an inverse trig function?
arcsin (sqrt2/2)??

Calc  bobpursley, Wednesday, October 26, 2011 at 10:29pm
arcsin(sqrt2/2 ) is a constant. The derivative of a constant is zero.

Calc  Hannah, Wednesday, October 26, 2011 at 10:29pm
oops mixed up 2 questionss haha

Calc  Hannah, Wednesday, October 26, 2011 at 10:31pm
to find an arcsin you would just have to memorize the unit circle right? so arccos of sqrt3/2 is 5pi/6?

Calc  bobpursley, Wednesday, October 26, 2011 at 10:33pm
yes, that is the easy way.

Calc  Steve, Thursday, October 27, 2011 at 11:10am
However, to find the derivative of an inverse trig function, go through the back door, as it were
y = arcsin(x)
sin y = x
cos y y' = 1
y' = 1/cos x = 1/√(1sin^{2}x) = 1/√(1x^{2})
Answer This Question
Related Questions
 Calculus (Derivatives of Inverse Functions)  Suppose f(x) = sin(pi cos(x)). On ...
 Calculus  Hello I need help with this excersise of derivative of a inverse ...
 trig  Find the exact values of the inverse function arcsin 1/2
 Inverse Trig  Using pi/2 ≤ y ≤ pi/2, what are the following ...
 math please help  use an inverse trig function to write theta as a function of ...
 MATH CHECK  COS[ARCSIN (SIN 3PI/4)] =COS[ARCSIN (SQRT2/2)] =COS [PI/4] = SQRT2/...
 trig  Write the expression and evaluate. There is only one answer whIch should ...
 Calc  Use the derivative to determine whether the function is strictly ...
 inverse  If f(x)=cosx + 3 how do I find f inverse(1)? Thanks y = cos(x) + 3 the...
 math  Eliminate the parameter (What does that mean?) and write a rectangular ...
More Related Questions