Monday

December 22, 2014

December 22, 2014

Posted by **Jen** on Wednesday, October 26, 2011 at 6:19pm.

(A) exactly two will have this mild side effect

(B) at least three will have this mild side effect.

I got this for (A):

= 14!/(14-2)!2! (0.10)²(0.90)14-2^2

= 14*13*12!/12!2*1(0.10)²(0.90)12^2

= 14*13/2*1(0.01)(0.28)

= 182/2(0.01)(0.28)

= 91(0.01)(0.28) = 0.25 or 25%

But i'm not sure how to do (B)

PLZZZZZ HELP!!!

- Did i do this right??? STATS -
**MathGuru**, Thursday, October 27, 2011 at 5:28pmA looks OK!

For B, use the same process. Since the problem says "at least 3" you will have to determine P(0), P(1), P(2). You already have P(2) from part A. Add P(0), P(1), and P(2) together. Then subtract that value from 1 for your probability.

I hope this helps.

- Did i do this right??? STATS -
**spam**, Friday, September 26, 2014 at 7:58pmSPAMA GUY!!! LOLOLATRA HAIL BIN LADIN!

**Answer this Question**

**Related Questions**

Can u help me Ms. Sue...Stats - In testing a new drug, researchers found that 10...

Stats - In testing a new drug, researchers found that 10% of all patients using ...

Stats - In testing a new drug, researchers found that 10% of all patients using ...

Can u plz help me PsyDag?? Stats - In testing a new drug, researchers found that...

PLZ help!! Stats.... - In testing a new drug, researchers found that 10% of all ...

stats - In testing a new drug, researchers found that 1% of all patients using ...

Statictics - In testing a new drug, researchers found that 20% of all patients ...

statistics - . In testing a new drug, researchers found that 20% of all patients...

Statistics - . In testing a new drug, researchers found that 20% of all patients...

Math - In testing a new drug, researchers found that 10% of all patients using ...