Chemistry
posted by Nadia on .
In the Formula...
Na+ + NO2 + HSO3NH2 > HSO4 + H2O + N2 + Na+
which I know has a 1:1 ratio, How do I figure out the Moles of N2 gas expected.
Molar volume = 24.627 L/mol
Moles of N2 produced = .0067 mol
Volume of N2 gas of STP = .165 L
Original used .5062g of NaNO2 to produce reaction.
Please Help!

moles NaNO2 = grams/molar mass?
I wonder why you used 24.627 for the molar volume? 
In the lab experiment (Ideal Gas Behaviour) we were told to calculate the Molar voume of N2 gas using the equation  vol N2 @STP/ mol N2 produced.
The mol of N2 produced were found using the equation PV=nRT
where P = Net pressure of N2 alone = 744.11 (tot pressure  vapour pressure of H2O)
V = .165 L (vol N2 @STP)
R = .082 constant
T = absolute temp of N2 = 295.35
Vol N2 @ STP was found using P1V1/T1 = P2V2/T2 
Thanks. So the 24.627 is your experimentally determined value.

Ok, so how then do I figure out the expected moles for N2 at the end of the equation. Is it that because of the 1:1 ratio that the .0073 mol of NaNO2 are the same for the N2 gas?

That's what I would do.