Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide:

CaO(s) + H2O(l) �¨ Ca(OH)2(s)
In a particular experiment, a 2.00-g sample of CaO is reacted with excess water and 2.14 g of Ca(OH)2 is recovered. What is the percent yield in this experiment?

You must first determine the theoretical yield. Here is an example. Just follow the steps. http://www.jiskha.com/science/chemistry/stoichiometry.html

The %yield = (actual yield/theoretical yield)*100 = ??

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To calculate the percent yield, we need to compare the actual yield to the theoretical yield.

Step 1: Calculate the molar mass of Ca(OH)2.
Ca: 1 mol × 40.08 g/mol = 40.08 g/mol
O: 2 mol × 16.00 g/mol = 32.00 g/mol
H: 2 mol × 1.01 g/mol = 2.02 g/mol
Total: 74.10 g/mol

Step 2: Calculate the theoretical yield of Ca(OH)2.
First, we need to calculate the number of moles of Ca(OH)2 produced using the given mass of CaO.
Molar mass of CaO (CaO): 1 mol × 40.08 g/mol + 1 mol × 16.00 g/mol = 56.08 g/mol
Number of moles of CaO: 2.00 g CaO × (1 mol CaO / 56.08 g CaO) = 0.0356 mol CaO

From the balanced equation, we know that 1 mol of CaO produces 1 mol of Ca(OH)2.
So, the number of moles of Ca(OH)2 produced is also 0.0356 mol.

Theoretical yield of Ca(OH)2: 0.0356 mol × 74.10 g/mol = 2.6416 g

Step 3: Calculate the percent yield.
Percent yield = (actual yield / theoretical yield) × 100

Percent yield = (2.14 g / 2.6416 g) × 100 ≈ 81.1%

Therefore, the percent yield in this experiment is approximately 81.1%.

To calculate the percent yield in this experiment, you need to compare the actual yield (the amount of Ca(OH)2 recovered) with the theoretical yield (the amount of Ca(OH)2 that would be produced if the reaction went to completion).

First, you need to determine the theoretical yield of Ca(OH)2. This can be calculated from the balanced equation. The molar ratio between CaO and Ca(OH)2 is 1:1, which means that for every 1 mol of CaO reacted, 1 mol of Ca(OH)2 is produced.

1 mol of CaO has a molar mass of 56.08 g/mol, so the number of moles of CaO can be calculated by dividing the mass of CaO by its molar mass:
2.00 g CaO / 56.08 g/mol CaO = 0.0356 mol CaO

Since the molar ratio between CaO and Ca(OH)2 is 1:1, the number of moles of Ca(OH)2 produced is also 0.0356 mol.

The molar mass of Ca(OH)2 is 74.09 g/mol, so the theoretical yield of Ca(OH)2 can be calculated by multiplying the number of moles by its molar mass:
0.0356 mol Ca(OH)2 × 74.09 g/mol Ca(OH)2 = 2.64 g Ca(OH)2

Next, you can calculate the percent yield by dividing the actual yield (2.14 g Ca(OH)2) by the theoretical yield (2.64 g Ca(OH)2) and multiplying by 100:
Percent Yield = (Actual Yield / Theoretical Yield) × 100
Percent Yield = (2.14 g / 2.64 g) × 100 = 81.06%

Therefore, the percent yield in this experiment is approximately 81.06%.