farmer montague raises chicken and goats. she is not sure how many she of each animal. but she does know she has 22 animals all together. She also know that all together,her animals have 56feet. How many of each type animall does farmer montague have?

Question

farmer montague raises chicken and goats. she is not sure how many she of each animal. but she does know she has 22 animals all together. She also know that all together,her animals have 56feet. How many of each type animall does farmer montague have?

Answer 1

Let C = # chickens and G = # goats.

2C + 4G = 56

C + G = 22

Multiply second equation by 2 and subtract it from the first equation.

2G = 12

G = 6

Insert that value into the first equation and solve for C. Check by inserting both values into the second equation.

Answer 2

5 chicken

8 goat

Answer 3

Let's assume the number of chickens is x, and the number of goats is y.

We know that:

1. The total number of animals is 22, so we can write the equation x + y = 22.

2. The total number of feet is 56, and chickens have 2 feet, while goats have 4 feet. So we can write the equation 2x + 4y = 56.

To solve this system of equations, we can first try to eliminate one variable. We can multiply the first equation by 2 to make the coefficients of x in both equations equal: 2(x + y) = 2(22) -> 2x + 2y = 44.

Now we have the system of equations:

2x + 2y = 44
2x + 4y = 56

Subtracting the first equation from the second equation, we can eliminate x:

(2x + 4y) - (2x + 2y) = 56 - 44
2y = 12
y = 6

Now we can substitute the value of y in the first equation to find x:

x + 6 = 22
x = 22 - 6
x = 16

Therefore, Farmer Montague has 16 chickens and 6 goats.

Answer 4

To solve this problem, we can use a system of equations. Let's assume the number of chickens as "x" and the number of goats as "y".

We know that the total number of animals is 22, so we can write the equation:

x + y = 22 (Equation 1)

Next, we have the information that the total number of feet is 56. Chickens have 2 feet and goats have 4 feet. Based on this, we can write another equation:

2x + 4y = 56 (Equation 2)

Now we have a system of equations:

x + y = 22 (Equation 1)
2x + 4y = 56 (Equation 2)

We can solve this system of equations using either substitution or elimination method.

Let's use the elimination method to solve the system:

Multiply Equation 1 by 2 to make the coefficients of "x" equal in both equations:

2(x + y) = 2(22)
2x + 2y = 44 (Equation 3)

Now, subtract Equation 3 from Equation 2 to eliminate the "x" term:

(2x + 4y) - (2x + 2y) = 56 - 44
2y = 12
y = 6

Substitute the value of y (6) back into Equation 1 to find the value of x:

x + 6 = 22
x = 16

Therefore, Farmer Montague has 16 chickens and 6 goats.