A ball rolls off of a table with a speed of 2 m/s. The table is 1.2 m high. How long will it take to the ball to hit the ground?
Drag out your good old formula
s = 1/2 at^2
You have s = 1.2
You have a = 9.8
Plug and chug
2.1m
2.1
To calculate the time it takes for the ball to hit the ground, we can use the equation for vertical motion under gravity:
h = (1/2) * g * t^2
Where:
h is the height of the table (1.2 m)
g is the acceleration due to gravity (9.8 m/s^2)
t is the time it takes for the ball to hit the ground (what we want to find)
Using this equation, we can rearrange it to solve for t:
t = sqrt((2*h) / g)
Let's substitute the given values into the equation:
t = sqrt((2 * 1.2) / 9.8)
Calculating this equation, we have:
t ≈ sqrt(0.24489796)
t ≈ 0.494
Therefore, it will take approximately 0.494 seconds for the ball to hit the ground.