February 27, 2017

Homework Help: Chemistry

Posted by Hannah on Wednesday, October 26, 2011 at 10:55am.

For a chemistry lab the experiment was to carry out an acid-base titration to determine the exact concentration of a sodium hydroxide solution.

Two trials were completed and the data collected was: mass of weighing paper, mass of weighing paper + KHP, mass of KHP, initial buret reading, final buret reading, and volume of NaOH.

The molecular weight of KHP is 204.44 grams/mol.

I need to find the number of moles of KHP, the number of moles of NaOH and the concentration of NaOH but i am not sure how to do this. Please help,thank you!!

so for the moles of KHP it would be 1/204.44 = 0.00489 g/mol?

The volume of NaOH for trial 1 was 14.50 mL and for trial 2 it was 9.90mL. so for molesof NaOH would it be 39.998 which is the molecular weight og NaOH divided by the volume for each trial?

Then for the concentration of NaOH would i use the number of moles that I got and divide that by the volumes of NaOH?

Thank you for your help! I am not very good with this chemistry stuff.

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