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March 3, 2015

Posted by **Eliyahna** on Wednesday, October 26, 2011 at 10:34am.

- Physics -
**bobpursley**, Wednesday, October 26, 2011 at 11:05amResultant=Sum of vectors

1000N=wind+headingspeed

1000N=(100*.707S+100*.707E)2.5+ (XXXXN+ XXXXE)2.5

solve for the N and E components.

I willdo N for you.

1000N=-70.7N*2.5 + XXXXN*2.5 so the north component has to be 471km/hr N

Now do the E component , (it might be negative, or W), then add the vectors to get flight speed, and direction.

- Physics -
**Eliyahna**, Wednesday, October 26, 2011 at 11:16amI do not understand...this is part of my lab questions for a force table lab, and we have not done Sum of Vectors in class at all... Why would you use 2.5hr in the multiplications? Would you not use the 1000km/2.5hr for the speed in some way? Also...I don't understand what you are doing in the second half of the equation... you are adding a NE heading to the SW heading of the wind to correct to go north?

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