Maths
posted by Vivian on .
A right pyramid on a base 4cm square has a slant edge of 6cm.calculate the volume of the pyramid

We need the perpendicular height of the pyramid.
Diagonal of base:
d^2 = 4^2 + 4^2 = 32
d= √32 = 4√2
then h^2 + (2√2)^2 = 6^2
h^2 = 36  8 = 28
h = √28
Volume = (1/3) base x height
= (1/3)(16)(√28) = (32/3)√7 cm^2 or appr. 28.22