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December 20, 2014

December 20, 2014

Posted by **Vivian** on Wednesday, October 26, 2011 at 7:20am.

- Maths -
**Reiny**, Wednesday, October 26, 2011 at 8:50amWe need the perpendicular height of the pyramid.

Diagonal of base:

d^2 = 4^2 + 4^2 = 32

d= √32 = 4√2

then h^2 + (2√2)^2 = 6^2

h^2 = 36 - 8 = 28

h = √28

Volume = (1/3) base x height

= (1/3)(16)(√28) = (32/3)√7 cm^2 or appr. 28.22

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