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December 20, 2014

December 20, 2014

Posted by **Alexis** on Tuesday, October 25, 2011 at 11:46pm.

- Calculus -
**Steve**, Wednesday, October 26, 2011 at 1:47pmAt the moment in question, the distance d = 250

x^2 + y^2 = d^2

2xx' + 2yy' = 2dd'

2(150)(-450) + 2(200)(-600) = 2(250)d'

Now, find d'

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