Posted by Steve on Tuesday, October 25, 2011 at 11:45pm.
Don't see much trig here.
R = (500-25x)(2+.25x)
= 1000 + 125x - 50x - 6.25x^2
= 1000 + 75x - 6.25x^2
R = -6.25(x^2 - 12x - 160)
= -6.25(x^2 - 12x + 36 - 160 - 36)
= -6.25(x-6)^2 - 600
So, the max occurs where x = 6
R(6) = 1225 when dogs cost $2 + 6*.25 = $3.50
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