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April 1, 2015

April 1, 2015

Posted by **Steve** on Tuesday, October 25, 2011 at 11:45pm.

- Algebra -
**Steve**, Wednesday, October 26, 2011 at 1:40pmDon't see much trig here.

R = (500-25x)(2+.25x)

= 1000 + 125x - 50x - 6.25x^2

= 1000 + 75x - 6.25x^2

R = -6.25(x^2 - 12x - 160)

= -6.25(x^2 - 12x + 36 - 160 - 36)

= -6.25(x-6)^2 - 600

So, the max occurs where x = 6

R(6) = 1225 when dogs cost $2 + 6*.25 = $3.50

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