Calculate the molarity of Na2C204 solution prepared by dissolving 1.2222 grams of pure Na2C204 in enough water to make 500.00 mL of solution.

Get the moles.

n = m/MM
n = 1.222grams / (Na2C2O4 Molar Mass)

Molarity = mole / volume
= [1.222g / (Na2C2O4 Molar Mass)]/0.500 L.

To calculate the molarity of a solution, we need to determine the number of moles of the solute (Na2C204) and then divide it by the volume of the solution in liters. Here's how to do it step by step:

1. Determine the number of moles of Na2C204:
- The molar mass of Na2C204 is calculated by summing the atomic masses of its constituent elements.
- Na2C204 = 2(Na) + C + 4(O)
- Na = 2 * 22.99 g/mol = 45.98 g/mol (atomic mass of sodium)
- C = 12.01 g/mol (atomic mass of carbon)
- O = 4 * 16 g/mol = 64 g/mol (atomic mass of oxygen)
- Molar mass of Na2C204 = 2 * 45.98 + 12.01 + 4 * 16 = 281.96 g/mol

2. Convert the mass of Na2C204 to moles:
- Given 1.2222 grams of Na2C204
- Moles of Na2C204 = Mass of Na2C204 / Molar mass of Na2C204
- Moles of Na2C204 = 1.2222 g / 281.96 g/mol

3. Convert the volume of the solution to liters:
- Given 500.00 mL of the solution
- Volume of solution (in liters) = 500.00 mL / 1000 mL/L

4. Calculate the molarity using the formula:
- Molarity (M) = Moles of solute (Na2C204) / Volume of solution (in liters)
- Molarity (M) = Moles of Na2C204 / Volume of solution (in liters)

Now you have all the information needed to calculate the molarity of the Na2C204 solution. Simply substitute the values into the equation to find the answer.