an adult exerts a force of 26n to pull a child across the snow on a sled. The rope joins the sled at an angle of 30 degrees above the horizontal. Ignoring friction, how much work is done in pulling the sled 390m?
please someone help me with this...!!
Work = f (cos thetha)d
Use this formula ..this is used when an angle is made with a sled or vehicle
To find the work done in pulling the sled, we need to know the force applied, the displacement, and the angle between the force and displacement.
In this case, the force exerted by the adult is 26 N, and the sled is pulled a distance of 390 m. However, we also need to consider the angle at which the force is applied, which is 30 degrees above the horizontal.
To calculate the work done, we can use the formula:
Work = Force x Displacement x cos(theta)
where theta is the angle between the force and displacement. In this case, theta is 30 degrees.
So, the work done is:
Work = 26 N x 390 m x cos(30 degrees)
Before we can calculate the final answer, we need to convert the angle from degrees to radians, as trigonometric functions in most programming languages and calculators work with radians. To convert degrees to radians, we multiply by pi/180.
So, the work done is:
Work = 26 N x 390 m x cos(30 degrees) = 26 N x 390 m x cos(30 degrees x pi/180)
Simplifying the equation:
Work = 26 N x 390 m x cos(0.5236 radians)
Calculating cos(0.5236 radians):
cos(0.5236 radians) ≈ 0.866
Now we can substitute the value back into the equation:
Work ≈ 26 N x 390 m x 0.866
Calculating the final result:
Work ≈ 8,339.16 Joules