Posted by Dana on Tuesday, October 25, 2011 at 8:40pm.
pH = 10; pOH = 4; (OH^-) = 1E-4
.............BOH ==> B^+ + OH^-
initial.......x......0......0
equil.......x-1E-4...1E-4..1E-4
Kb = (B^+)(OH^-)/(BOH)
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