The legs of an isosceles triangle measure 2x+ 5 and 3x-1. Find the values of x.

The "legs" of an isosecles triangle are the two sides with equal length. Set them equal and solve for x.

2x + 5 = 3x - 1

x = 6

14/5=x/3

To find the values of x in this problem, we can use the fact that the lengths of the legs of an isosceles triangle are equal.

In this case, we have the lengths of the legs as 2x + 5 and 3x - 1. Therefore, we can set up an equation:

2x + 5 = 3x - 1

To solve this equation, we need to isolate the variable x on one side of the equation. Let's do it step by step:

First, let's get rid of the x term on the right side by subtracting 2x from both sides:

2x + 5 - 2x = 3x - 1 - 2x

Simplifying, we have:

5 = x - 1

Next, let's isolate the x term by adding 1 to both sides:

5 + 1 = x - 1 + 1

Simplifying further, we get:

6 = x

Therefore, the value of x is 6.

So, the solution for this problem is x = 6.