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March 29, 2015

Homework Help: Algebra 2

Posted by Anonymous on Tuesday, October 25, 2011 at 7:10pm.

"My husband's age," remarked a lady the other day, "is represented by the figures of my own age reversed. He is my senior, and the difference between our ages is one-eleventh of their sum."
10x + y = husband's age
10y + x = wife's age
(10x+y) - (10y+x) = ((10x+y) + (10y+x))
10x + y - 10y - x = (10x + y + 10y + x)
9x - 9y = (11x + 11y)
9x - 9y = 11(x + y)
9x - 9y = x + y
9x - x = 9y + y
8x = 10y
x = y
x = 1.25y
How do you get the answer Husband is 54, wife is 45. I understand how to set it up and solve it, now how do i figure out their ages?

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