Posted by Sophie on Tuesday, October 25, 2011 at 5:24pm.
An engineer is desingning a parabloic arch, the arch must be 15 m high , and 6 m wide, at a height of 8 m
a) determine a quadratic fundtion that satisfies these conditions
b) what is the width of the arch at its base

Math  Steve, Wednesday, October 26, 2011 at 4:42am
Let the arch be centered on the yaxis. Then the equation will be
y = ax^2 + k
It will have height 6 at x = 3 and 3
The vertex will be at (0,15)
y = ax^2 + 15
6 = a(3^2) + 15
6 = 9a + 15
9 = 9a
a = 1
y = x^2 + 15
y=0 when x^2 = 15, so the width is 2√15 at its base

Math  stephen, Thursday, January 19, 2017 at 12:35pm
Roof of a tunnel is in the shape of parabolic arch whose highest point is 18m above a road. The road surface is 16m wide at ground level. Lights are placed in the tunnel 12 m high. How far from the center of the tunnel are the lights placed?
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