Calculate the sodium ion concentration when 50.0 mL of 2.0 M Na2CO3 is added to

100.0 mL of 3.0 M NaHCO3

50.0mL x 2.0M Na2CO3 = 100 millimoles Na2CO3 = 200 mmoles Na^+.

100 mL x 3.0M NaHCO3 = 300 mmoles Na^+.
(mmoles Na^+ from 1 + mmoles Na^+ from 2)/total volume in mL = M Na+

To calculate the sodium ion concentration when Na2CO3 is added to NaHCO3, we first need to determine the number of moles of each compound.

Step 1: Calculate the moles of Na2CO3:
Molarity = Moles / Volume
2.0 M = Moles / 0.050 L
Moles = 2.0 M * 0.050 L
Moles = 0.10 moles

Step 2: Calculate the moles of NaHCO3:
Molarity = Moles / Volume
3.0 M = Moles / 0.100 L
Moles = 3.0 M * 0.100 L
Moles = 0.30 moles

Step 3: Calculate the moles of sodium ions (Na+):
In Na2CO3, there are 2 moles of sodium ions for every 1 mole of compound.
Moles of Na+ in Na2CO3 = 2 * 0.10 moles = 0.20 moles

In NaHCO3, there is 1 mole of sodium ions for every 1 mole of compound.
Moles of Na+ in NaHCO3 = 1 * 0.30 moles = 0.30 moles

Step 4: Calculate the total moles of sodium ions:
Total moles of Na+ = Moles of Na+ in Na2CO3 + Moles of Na+ in NaHCO3
Total moles of Na+ = 0.20 moles + 0.30 moles
Total moles of Na+ = 0.50 moles

Step 5: Calculate the total volume:
Total volume = Volume of Na2CO3 + Volume of NaHCO3
Total volume = 0.050 L + 0.100 L
Total volume = 0.150 L

Step 6: Calculate the concentration of sodium ions:
Concentration = Total moles of Na+ / Total volume
Concentration = 0.50 moles / 0.150 L
Concentration = 3.33 M

Therefore, the sodium ion concentration is 3.33 M when 50.0 mL of 2.0 M Na2CO3 is added to 100.0 mL of 3.0 M NaHCO3.