Calculus
posted by Anonymous on .
A rancher plans to make four identical and adjacent rectangular pens against a barn, each with an area of 100m^2. what are the dimensions of each pen that minimize the amount of fence that must be used?

If each pen has width x and length y (against the barn),
the area is 4xy, and the fence used is 5x+8y
So, each pen has area 100.
p = 5x + 8(100/x) = 5x + 800/x
dp/dx = 5  800/x^2
dp/dx = 0 when x = √160 = 4√10
x = 4√10
y = 25/√10 
Now, if the barn is used as one wall of the pen, meaning only 3 sides have to be fenced, then
p = 5x+4y = 5x + 4(100/x) = 5x + 400/x
p' = 5  400/x^2
p' = 0 at x = 4√5
y = 25/√5