Discrete Math
posted by Bobbi on .
Prove that if a and b are integers with a not equal to zero and x is a real number such that ax^2bxba=0, then a  b. Note a  b means that a divides b.

Is something wrong here?
3x^2 + 4x + 1 = 0
x = 1 or 1/3
a = 3, b = 4
a does not divide b