Posted by **Danielle** on Tuesday, October 25, 2011 at 8:15am.

Seven standard, six-sided dice are rolled, one after the other. What is the probability that:

a) exactly one of them shows a six?

c) there is at least one that shows a six?

- Math -
**Reiny**, Tuesday, October 25, 2011 at 8:47am
prob(6) = 1/6

prob(not6) = 5/6

a) exactly 1 out of 7 tries to be 6

= C(7,1) * (1/6)^1 * (5/6)^6

= .3907 rounded to 4 decimals

b) at least one 6 ---> 1 - prob(all not6)

= 1 - C(7,7) * (1/6)^0 * (5/6)^7

= 1 - .2791

= .7209

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