Posted by Danielle on Tuesday, October 25, 2011 at 8:15am.
prob(6) = 1/6
prob(not6) = 5/6
a) exactly 1 out of 7 tries to be 6
= C(7,1) * (1/6)^1 * (5/6)^6
= .3907 rounded to 4 decimals
b) at least one 6 ---> 1 - prob(all not6)
= 1 - C(7,7) * (1/6)^0 * (5/6)^7
= 1 - .2791
= .7209
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